35x^2+2x-48=21877

Solution for 35x^2+2x-48=21877 equation:

35x^2+2x-48=21877

We move all terms to the left:

35x^2+2x-48-(21877)=0

We add all the numbers together, and all the variables

35x^2+2x-21925=0

a = 35; b = 2; c = -21925;
Δ = b2-4ac
Δ = 22-4·35·(-21925)
Δ = 3069504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3069504}=1752$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-1752}{2*35}=\frac{-1754}{70}
=-25+2/35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+1752}{2*35}=\frac{1750}{70}
=25
$